Clegg Hammer Modulus
•Looking first for Vertical Displacement under the centre of the applied loading (Δ) and then solving for the modulus of elasticity (E), with certain assumptions:
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•Δ = 2 (p )(a) (1 – μ2) / E
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•Where p = contact pressure, a = the radius of applied circle of loading, E = the modulus of elasticity and μ = Poisson’s ratio. Assuming Poisson’s ratio is 0.5, then:
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• Δ = 1.5 (p )(a ) / E
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•For a rigid plate (i.e. Clegg Hammer) rather than a flexible plate then:
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•Δ = 1.18 (p ) (a ) / E
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•Calculating p from force (Clegg Hammer Mass x Acceleration due to gravity) and the acceleration (deceleration, Gm, i.e. value as measured by the Clegg Hammer times 10), where the Clegg Hammer radius (in metres) and drop-height (in metres)  factor into it, and applying an additional factor of 0.6 for converting square wave used in maths to ½ sin wave type shape as observed on actual impacts on compacted soils using a CRO and solving now for E (in Pascals), this becomes:
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•E = (1.18) (9.81) (0.6) (Gm ) (Gm) (Hammer Mass ) / π (Hammer Radius) (Drop-Height)
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